Frequently Asked Questions

Table of Contents

 

What is wrong with helicity?

Helicity is not well-defined in the rest frame and it depends on the reference frame. Helicity is determined by the momentum and spin orientation of a particle. We should be weary of two critical and subtle points. First, there is no momentum when the particle is in the rest frame and thus its helicity is not well-defined. This point is consistent with the accurate solution of the Dirac equations for massive fermion, where no left-handed or right-handed helicity is available. Second, the helicity of massive fermion changes under the Lorentz transforamtions as its signs of momentum reversed. These problems do not arise in massless particle as there is no rest frame when massless. We may find a historical reason why these points have been neglected from the fact that the concept of helicity has been developed from the study of nuetrino, assumed massless then.

 

 

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Why do we care whether an approximation violates Lorentz invariance?

Because it limits the truth the approximation indicates!. One may dismiss any violation of principle in approximation, saying that the approximation is just an approximation. However there is a good reason for this and it concerns the criteria of scientific logic. Let us say there is a person A walking on the street and I observe that person A closely resembles person B I know. Without any further assumptions or known facts, this approximate observation can tell either A is B or A is similar to B. On the contrary, if I am with person B right now, this approximation is limited to indicate that person A is a look-alike of person B, not A is B. In other words, if we have a fact or assumption that contradict any possible logical consequence of approximation observation, this would limit its approximation for reveal what is true. In E158, we approximately measure the helicity of electron or muon in the laboratory frame and rely on the Standard Model for its calculations. However, we should be cautious to conclude parity, a fundamental property of nature, is violated and rather investigate any lack of rigor from this approximation of helicity. For example, we can observe the Left-Right asymmetry in E158 as a Right-Right asymmetry in any frame and thus the Left-Right asymmetry is not a Lorentz-invariant observable.

 

 

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Isn’t partity violated in weak interactions regradless of whether or not neutrino have mass?

No, the historical background to conclude parity violation is not free of massless neutrino assumption. There are different types of parity violation(atomic beta decay, neutral meson, neutrino: note the first two are composite) and they are only assumed to be universal. The conclusion of parity violation is based on the assumption of massless neutrino, which is quite essential since it is only evidence directly related to point-like and fundamental particle. How come we keep insisting that the logical consequence of massless neutrino still holds without any further investigation when we find it massive?  

 

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Why does parity violation imply Lorentz violation?

Parity violation is Lorentz violation for massive fermon. Consider a massive fermion with left-handed helicity. Under parity, the massive fermion is supposed to be transformed into the right-handed helicity. However, we can find the exactly same transformation under the Lorentz transformations; the left-handed massive fermion can be observed as a right-handed helicity one as its momentum becomes reversed in the boosted frame. Therefore, what parity operator does to a massive fermion is the same as Lorentz transformationa and the parity violation means Lorentz violation for massive fermion.

 

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What is difference btween chirality of fermon and that of interactions?

Whether electromagnetic(EM) and weak interactions is unified or not. The chirality of fermion can only be an observable property when the fermion is massless as it becomes idential to helicity. For a massive fermion, there is always two chirality to represent the fermion state according to the Dirac equations. In other word, no massive particle can be designated as, for example, a left-handed chirality fermion.

 

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Isn’t the Standard Model based on the assumption of massless neutrino, not massless fermion?

No. Accurately speaking, it is not  exactly free of massless fermion assumption as long as the fermion with a massive term described with the property of massless fermion. In the Standard Model, we start with massless fermion that can be labeled as left- and right-handed chirality and helicity as they are the same for massless fermion. After the Higgs mechanism of spontaneous symmetry breaking, the massless fermion obtains a mass term. However, it treats these massivee fermion labeling as left-handed or right-handed as if there were massless, while there is no massive particle with only one chirality. There are two justification arguments in general. First, one may claim now this left- and right-handedness is either of helicity or of chirality which can be approximately the same in the high energy limit or the massless limit. This means that the Standard Model is only approximately true, but since this approximation violates Lorentz invariance, the implication of this approximation reflecting a rigorous truth of fundamental property of nature should be excluded and we must conclude that the Standard Model is seemingly true, but not true. Second, one may say the calculation would be the same whether massive or not as the chiral structure of weak interaction picks up only one of two Weyl spinors. This statement is inconsistent with the whole idea of the Standard Model of unification of electroweak interactions, since the concept of chiral structure indicates that the weak interactions structure is fundamentally different from electromagnetic interactions.

 

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Isn’t the Standard Model Lorentz invariant?

No, it is not, exactly. Since the Standard Model interaction is Lorentz-scalar, one may prove its Lorentz invariance with an assumption of massless fermion, i.e. as long as we describe a massive fermion with only one chirality. If then, this fermion with one chirality would remain the same regardless of its reference frame. But what it matters is whether it is Lorentz-scalar of a particle satisfying the Dirac equations. And there is no such massive fermion according to the Dirac equations; any massive fermion should have two nonzero Weyl spinors. One may say one of the Weyl spinor is suppressed in the boosted frame. Yes, it is, but it is only small, not zero. This is only approximation which violates Lorentz violation. Then, this proof is inconsistent, since we have proved that a theory is Lorentz invariance with an assumption of Lorentz vioation.

 

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Why is Higgs mechanism hypothetical?

Because it does not have any specifics of physical time and space. A physicsal event specifies its physical time and space. If an event does not carry any concept of physics time and space that we can observed and measure, it is not a physical event, but a hypothetical one.

 

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Are you not confused with helicity and chiraltiy?

No, though it is quite common to confuse with helicity and chirality. I believe what I have discussed in my article is more subtle than people think and that is why my explanation deals with explicit details.

 

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Why the discrete symmetry is irrelevant of lifetime?

Because the actual calculation of lifetime is independent of the signs of coupling constants as it takes the absolute value of interacting term. The lifetime calculation is based on the assumption of local interactions. This assumption treats particles as free separating its interactions as we solve the free Dirac equation, rather than the interacting ones. Therefore, the Dirac field we use for the lifetime calculation do not carry any information about the signs of its coupling constants.

 

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Isn’t the Standard Model based on the Higgs mechanism, not just the Dirac equations?

Yes and that is why we can say that the SM denies the fundamentaliy of Dirac equaitons. My article is clearly based on the fundamentality of Dirac equations while the Standard Model implies that the Dirac equations are not completely fundamental equations to determine the properties of fermions, but it requires some other explanation of Higgs field. If that is where the SM stands at, then it should Cleary state that "the Dirac equation is not fundamental, but the Higgs mechanism is more fundamental one", but no where in the SM makes such a clear statement. Also, our practical understanding of fermion is mainly based on the fundamentality of the Dirac equations. At least, the Dirac equation is still commonly accepted as fundamental in most references we can find including textbooks. If we would like to deny the Dirac equations, we need a more cautious approach then the way the Higgs mechanism has been upheld so far. After all, the Higgs mechanism has not been verified yet and is still hypothetical as we do not have the specific space and time information about the occurrence of symmetry breaking. That is why I think it is a weak argument to deny that the Dirac equations is not fundamental and at least it is worthy of our rigorous investigation.

 

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Isn’t an interacting Dirac field different from the free Dirac field?

Yes, an interacting field could be different from a free field. However, in practice, we do NOT solve the interacting Dirac equations, but rely on the free Dirac equations assuming the locality of interactions,  i.e. asymptotic completeness. Therefore, the inconsistencies arise from the basic assumption of QFT and we cannot dismiss my argument as inconsistent as long as QFT is established on the same view. As a matter of fact, this conventional approach of quantum field theory brings the interacting field  back to the free field, which is at least practical way to evaluate interactions. This is exactly where the fundamentality of symmetry fails and is limited by our practical calculation.

 

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Isn’t it usual for a quantum field to have a conceptual problem?

Yes, quantum fields are quantum fields, but the rigor of mathematics and any failure should be explicitly clarified. What lies in this question is that quantum fields do not need to obey mathematical representation rigorously. In my paper I take a point of view of investigating with the rigor of mathematical reasoning. It could be reasonable to have flexible physical interpretations, but it is not a good reason to claim its rigorousness or dismiss a rigorous argument.

 

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Last revised: 01/25/2006